: Solve these questions to crack the SI exams #IndiaNEWS #Education Today Hyderabad: This article is in continuation to the last article on preparation for the Sub-Inspector of Police recruitment exam.

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Solve these questions to crack the SI exams #IndiaNEWS #Education Today
Hyderabad: This article is in continuation to the last article on preparation for the Sub-Inspector of Police recruitment exam. Here are some practice questions and solutions on the Time and Distance topic.
 

If a person travelled at 56 km/hr instead of 48 km/hr, he would have travelled 40 km more in same time. Find the actual distance travelled by him?

Solution:
S1 = 48 km/hr                    S2 = 56 km/hr
D1 = x km                            D2 = (x + 40) km
T   = x/48 hrs                       T  =  x+40/56 hrs
Both the cases, time is same
So  => 56x = 48x + 1920
8x = 1920
X = 240 km.
Simple Method:
Increased Speed              = 56 – 48 = 8 km/hr
Increased Distance          = 40 km/hr
Time                                      = 40 / 8 = 5 hrs
Actual Distance                 = 5 × 48 = 240 km

The distance between A and B is 650 km. A person travelled from A to B at 60 km/hr and started at 9 am and another person travelled from B to A at 70 km/hr and started at same time. Then at what time they meet together?

Solution:
Both persons are started at same time
Let 9 am after ‘x’ hours, they meet together
So the sum of distance covered by 1st person in ‘x’ hours and distance covered by second person in ‘x’ hours should be equal to 650 km
60x + 70x = 650
130x = 650
X = 5 hrs
9 am after 5 hours means 2 pm
At 2 pm, they meet together.
Simple Method:
Relative Speed = 60 + 70 = 130 km/hr
Distance               = 650 km
Time                      = 650 / 130 = 5 hours
9 am after 5 hours means 2 pm

The distance between A and B is 490 km. A person travelled from ‘A’ to ‘B’ 40 km/hr and started at 9 am, after one hour another person travelled from ‘B’ to ‘A’ at 50 km/hr. Then what time they meet together?

Solution:
Both the persons are not started at same time.
Let 9 am after ‘x’ hours, they meet together.
So the sum of distance covered by 1st person in ‘x’ hours and distance covered by second person in ‘x – 1’ hours should be equal to 490 km
40x + 50(x – 1)   = 490
40x + 50x – 50    = 490
90x                         = 540
X                             = 6 hours
X = 6 hrs
9 am after 6 hours means 3 pm
At 3 pm, they meet together.

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